CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: What is the next number of the following sequence ? 21, 77, 165, 285, ...... 2406 05b5cc74ae4d2b4197774fab8
5b5cc74ae4d2b4197774fab8- 1404false
- 2415false
- 3426false
- 4437true
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उत्तर : 4. "437"
व्याख्या :
Answer: D) 437 Explanation: The series follow the rule, 21 = 77 = 92-4165 = 132-4285 = 172-4 5,9,13,17,21,(+4)...In the same way next no. will be 212-4 = 441 - 4 = 437
प्र: The product of two positive numbers is p. If each of the numbers is increased by 2, the new product is how much greater than twice the sum of the two original numbers ? 1764 05b5cc74ae4d2b4197774faae
5b5cc74ae4d2b4197774faae- 1p timesfalse
- 22p timesfalse
- 3(p + 4) timestrue
- 4(2p + 3) timesfalse
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उत्तर : 3. "(p + 4) times"
व्याख्या :
Answer: C) (p + 4) times Explanation: Let the two no's be a and b;Given product of the no's is p = ab;If the each nos is increased by 2 then the new product will be (a+2)(b+2) = ab + 2a + 2b + 4= ab + 2(a+b) + 4= p + 2(a+b) + 4Hence the new product is (p+4) times greater than twice the sum of the two original numbers.
प्र: Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ? 4855 05b5cc74ae4d2b4197774faa4
5b5cc74ae4d2b4197774faa4- 124 $false
- 222 $false
- 316 $true
- 414 $false
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उत्तर : 3. "16 $"
व्याख्या :
Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.
प्र: Find the missing number in the given series ? 15, 51, 216, 1100, ?, 46452 3689 05b5cc74ae4d2b4197774faa9
5b5cc74ae4d2b4197774faa9- 15660false
- 26560false
- 36750false
- 46630true
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उत्तर : 4. "6630"
व्याख्या :
Answer: D) 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.
प्र: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2469 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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उत्तर : 2. "14"
व्याख्या :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
प्र: There are 44 students in a hostel, due to the administration, 15 new students has joined. The expense of the mess increase by Rs. 33 per day. While the average expenditure per head diminished by Rs. 3, what was the original expenditure of the mess ? 2346 05b5cc74ae4d2b4197774fa9f
5b5cc74ae4d2b4197774fa9f- 1Rs. 404false
- 2Rs. 514false
- 3Rs. 340false
- 4Rs. 616true
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उत्तर : 4. "Rs. 616"
व्याख्या :
Answer: D) Rs. 616 Explanation: Let the average expenditure per head be Rs. pNow, the expenditure of the mess for old students is Rs. 44pAfter joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33Therefore, 59(p-3) = 44p + 3359p - 177 = 44p + 3315p = 210 => p = 14Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.
प्र: A man sell 35 waffers for Rs. 15 each and loses Rs. 40.4. If he sells 35 waffers for Rs. 18, how much does he loss or gain ? 1091 15b5cc74ae4d2b4197774fa95
5b5cc74ae4d2b4197774fa95- 1Rs. 64true
- 2Rs. 52false
- 3Rs. 72false
- 4Rs. 55false
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उत्तर : 1. "Rs. 64"
व्याख्या :
Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.
प्र: A Cricket team of 23 people all shake hands with each other exactly once. How many hand shakes occur ? 2827 05b5cc74ae4d2b4197774fa90
5b5cc74ae4d2b4197774fa90- 1142false
- 2175false
- 3212false
- 4253true
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उत्तर : 4. "253"
व्याख्या :
Answer: D) 253 Explanation: The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on... So, 22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.