Answer: D) 437 Explanation: The series follow the rule,   21 = 77 = 92-4165 = 132-4285 = 172-4 5,9,13,17,21,(+4)...In the same way next no. will be 212-4 = 441 - 4 = 437

Answer: C) (p + 4) times Explanation: Let the two no's be a and b;Given product of the no's is p = ab;If the each nos is increased by 2 then the new product will be (a+2)(b+2) = ab + 2a + 2b + 4= ab + 2(a+b) + 4= p + 2(a+b) + 4Hence the new product is (p+4) times greater than twice the sum of the two original numbers.

Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.

Answer: D) 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.

Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14

Answer: D) Rs. 616 Explanation: Let the average expenditure per head be Rs. pNow, the expenditure of the mess for old students is Rs. 44pAfter joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33Therefore, 59(p-3) = 44p + 3359p - 177 = 44p + 3315p = 210 => p = 14Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.

Answer: D) 253 Explanation: The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on... So, 22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.