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प्र: A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? 1239 0

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    107 kmph
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  • 2
    106 kmph
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  • 3
    72 kmph
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  • 4
    76 kmph
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    गलत
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उत्तर : 2. "106 kmph"
व्याख्या :

Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.

प्र: Statement: Air export volumes have increased substantially over the past decade causing backlogs and difficulties for air cargo agents because of increased demand for space and service.Courses of action:a. Airlines and air cargo agents should jointly work out a solution to combat the problem.b. The reasons for the increase in the volume of air exports should be found out. 1535 0

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    Only a follows
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  • 2
    Both a and b follows
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  • 3
    Only b follows
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  • 4
    Neither a nor b follows
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उत्तर : 1. "Only a follows"
व्याख्या :

Answer: A) Only a follows Explanation: The problem faced, by the airlines and cargo agents is the non availability of cargo space. Therefore, right course of action is to combat the problem.

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उत्तर : 4. "Neither a nor b follows"
व्याख्या :

Answer: D) Neither a nor b follows Explanation: Financial support to the tourism sector is not a permanent solution. Secondly, constant risk for the foreign tourists will never encourage tourism in India. Hence, none of the course action is the right solution in this direction.

प्र: A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph. 1952 0

  • 1
    4314
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  • 2
    4213
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  • 3
    2413
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  • 4
    3414
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उत्तर : 2. "4213"
व्याख्या :

Answer: B) Option B Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmphtime taken indivisually: => 6/1.5 = 4 m=> 8/2 = 4 m=> 40/8 = 5 m   Average speed of man= total distance/ total time=> 54/13 = 4213 kmph

प्र: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 1733 0

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    100 mts
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  • 2
    96 mts
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  • 3
    98 mts
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  • 4
    120 mts
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उत्तर : 3. "98 mts"
व्याख्या :

Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.

प्र: Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds? 973 0

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    1:7
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  • 2
    7:1
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  • 3
    2:3
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  • 4
    3:2
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उत्तर : 1. "1:7"
व्याख्या :

Answer: A) 1:7 Explanation: Let the speed of the trains be x and y respectively length of train1 = 47xlength of train2 = 31yRelative speed= x + yTime taken to cross each other = 33 s=> 47x+31yx+y= 33=> (47x + 31 y) = 33(x + y)=> 14x = 2y=> x/y = 2/14 = 1/7  = 1:7

प्र: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ? 1387 0

  • 1
    2/3
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  • 2
    1/2
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  • 3
    7/8
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  • 4
    4/5
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उत्तर : 2. "1/2"
व्याख्या :

Answer: B) 1/2 Explanation: Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18 Multiples of 5 below 20 are 5, 10, 15, 20 Required number of possibilities = 10Total number of possibilities = 20Required probability = 10/20 = 1/2.

प्र: Three unbiased coins are tossed. What is the probability of getting at most two heads ? 1392 0

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    4/3
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  • 2
    2/3
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  • 3
    3/2
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  • 4
    3/4
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उत्तर : 4. "3/4"
व्याख्या :

Answer: D) 3/4 Explanation: Let S be the sample space.Here n(S)= 23 = 8Let E be the event of getting atmost two heads. Then,n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}Required probability = n(E)/n(S) = 6/8 = 3/4.

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