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Q: Two bottles contains mixture of milk and water. First bottle contains 64% milk and second bottle contains 26% water. In what ratio these two mixtures are mixed so that new mixture contains 68% milk?

  • 1
    3 : 2
  • 2
    2 : 1
  • 3
    1 : 2
  • 4
    2 : 3
  • Show Answer
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Answer : 1. "3 : 2"
Explanation :

Answer: A) 3 : 2 Explanation: % of milk in first bottle = 64% % of milk in second bottle = 100 - 26 = 74% Now, ATQ   64%            74%                   68%   6                    4   Hence, by using allegation method,   Required ratio = 3 : 2

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