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1220

Q: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ?

  • 1
    2580
  • 2
    3687
  • 3
    4320
  • 4
    5460
  • Show Answer
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Answer : 3. "4320"
Explanation :

Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.

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