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Q: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

  • 1
    99
  • 2
    100
  • 3
    89
  • 4
    1
  • Show Answer
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Answer : 1. "99"
Explanation :

Answer: A) 99 Explanation: Let, Distance between A and B = d   Distance travelled by P while it meets Q = d + 11   Distance travelled by Q while it meets P = d – 11   Distance travelled by Q while it meets R = d + 9   Distance travelled by R while it meets Q = d – 9   Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11   The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9   But given Ratio of speeds of P & R => P : R = 3 : 2  SPSR = SPSQxSQSR = d+11d+9d-11d-9   => d+11d+9d-11d-9 = 3/2   =>  d = 1, 99   => d = 99 satisfies.   Therefore, Distance between A and B = 99

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