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Q: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ?

  • 1
    6/7
  • 2
    19/21
  • 3
    7/31
  • 4
    5/21
  • Show Answer
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Answer : 4. "5/21"
Explanation :

Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21

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