If $$ {x+{9\over x}=6}$$ then find the value of $$ {x^{2}+{1\over x^{3}}}$$
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Q:
If $$ {x+{9\over x}=6}$$ then find the value of $$ {x^{2}+{1\over x^{3}}}$$
- 1$$ {12{1\over 27}}$$false
- 2$$ {9{1\over 27}}$$true
- 3$$ {8{1\over 27}}$$false
- 4$$ {10{1\over 27}}$$false
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