यदि $$ {x^{4}+x^{2}y^{2}+y^{4}={21\over256}}$$ और $$ {x^{2}+xy+y^{2}={3\over16}}$$ है तो तब $$ {2(x^{2}+y^{2})}=?$$ होगा।
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Q:
यदि $$ {x^{4}+x^{2}y^{2}+y^{4}={21\over256}}$$ और $$ {x^{2}+xy+y^{2}={3\over16}}$$ है तो तब $$ {2(x^{2}+y^{2})}=?$$ होगा।
- 1$$ {3\over 8}$$false
- 2$$ {5\over 8}$$true
- 3$$ {3\over 4}$$false
- 4$$ {5\over 16 }$$false
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