Get Started
358

Q:

यदि $${secθ={a\over b},b≠0,}$$ तो  

 $${{1-tan^2θ}\over 2-sin^2θ}=?$$  

  • 1
    $${b^2(2b^2-a^2)}\over {a^2(a^2+b^2)}$$
  • 2
    $${a^2(2b^2-a^2)}\over {b^2(a^2+b^2)}$$
  • 3
    $${a^2(2b^2+a^2)}\over {b^2(a^2+b^2)}$$
  • 4
    $${a^2(2b^2+a^2)}\over {b^2(a^2-b^2)}$$
  • Show Answer
  • Workspace

Answer : 2. "$${a^2(2b^2-a^2)}\over {b^2(a^2+b^2)}$$"

The Most Comprehensive Exam Preparation Platform

Get the Examsbook Prep App Today