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Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?

  • 1
    A is eldest & C is youngest
  • 2
    D is eldest & C is youngest
  • 3
    C is eldest & A is youngest
  • 4
    A is eldest & B is youngest
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Answer : 2. "D is eldest & C is youngest"
Explanation :

Answer: B) D is eldest & C is youngest Explanation: Given sum of present ages of A, B, C & D A + B + C + D = 176 and also given that, (A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14 Let the ratio = x => A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x => (A + B + C + D ) - 16 = 40x => 176 - 16 = 40x => x = 4 => A = 44 + 4 = 48 => B = 40 => C = 28 => D = 60 Therefore, from the above conclusions D is eldest with 60 years and C is youngest with 28 years of ages.

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