Get Started
1147

Q: Find the sum of the all the numbers formed by the digits 2,4,6 and 8 without repetition. Number may be of any of the form like 2,24,684,4862 ?

  • 1
    133345
  • 2
    147320
  • 3
    13320
  • 4
    145874
  • Show Answer
  • Workspace

Answer : 2. "147320"
Explanation :

Answer: B) 147320 Explanation: Sum of 4 digit numbers = (2+4+6+8) x P33 x (1111) = 20 x 6 x 1111 = 133320  Sum of 3 digit numbers = (2+4+6+8) x P23 x (111) = 20 x 6 x 111 = 13320  Sum of 2 digit numbers = (2+4+6+8) x P13 x (11) = 20 x 3 x 11 = 660  Sum of 1 digit numbers = (2+4+6+8) x P03 x (1) = 20 x 1 x 1 = 20    Adding All , Sum = 147320

The Most Comprehensive Exam Preparation Platform

Get the Examsbook Prep App Today