Answer : 2. "1/204"
Explanation :

Answer: B) 1/204 Explanation: Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then   Required probability = PA∩B∩C  = PA PBA PCA∩B  Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9 When  a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white  ∴PBA=317  Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white.  ∴PCA∩B =216=18  Hence the required probability = 29×317×18=1204