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Q: A can do a work in 9 days, B can do a work in 7 days, C can do a work in 5 days. A works on the first day, B works on the second day and C on the third day respectively that is they work on alternate days. When will they finish the work ?

  • 1
    [7 + (215/345)] days
  • 2
    [6 + (11/215)] days
  • 3
    [6 + (261/315)] days
  • 4
    [5 + (112/351)] days
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Answer : 3. "[6 + (261/315)] days"
Explanation :

Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315.   Now remaining work =  29 /315   On day 7, A will work again    Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.   Since he takes 9 days to finish the total task, he will need 261/315 of the day.    Total days required is 6 + (261/315) days.

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