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Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

  • 1
    2880
  • 2
    1440
  • 3
    720
  • 4
    2020
  • Show Answer
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Answer : 1. "2880"
Explanation :

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd.   4 women can be arranged at 4 even places in 4! ways.   and 5 men can be placed in remaining 5 places in 5! ways.   Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

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